1)
Answer:
Compiler Error
Explanation:
Initialization should not be done for structure members inside the structure declaration
2)
Answer:
Compiler Error
Explanation:
in the end of nested structure yy a member have to be declared.
3)
Answer:
Linker error: undefined symbol '_i'.
Explanation:
extern declaration specifies that the variable i is defined somewhere else. The compiler passes the external variable to be resolved by the linker. So compiler doesn't find an error. During linking the linker searches for the definition of i. Since it is not found the linker flags an error.
4)
Answer:
Compiler error: undefined symbol out in function main.
Explanation:
The rule is that a variable is available for use from the point of declaration. Even though a is a global variable, it is not available for main. Hence an error.
5)
Answer:
100
Explanation:
This is the correct way of writing the previous program.
#include<stdio.h> main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s=malloc(sizeof(struct xx)); printf("%d",s->x); printf("%s",s->name); }
Answer:
Compiler Error
Explanation:
Initialization should not be done for structure members inside the structure declaration
2)
#include<stdio.h> main() { struct xx { int x; struct yy { char s; struct xx *p; }; struct yy *q; }; }
Answer:
Compiler Error
Explanation:
in the end of nested structure yy a member have to be declared.
3)
main(){ extern int i; i=20; printf("%d",sizeof(i)); }
Answer:
Linker error: undefined symbol '_i'.
Explanation:
extern declaration specifies that the variable i is defined somewhere else. The compiler passes the external variable to be resolved by the linker. So compiler doesn't find an error. During linking the linker searches for the definition of i. Since it is not found the linker flags an error.
4)
main() { printf("%d", out); } int out=100;
Answer:
Compiler error: undefined symbol out in function main.
Explanation:
The rule is that a variable is available for use from the point of declaration. Even though a is a global variable, it is not available for main. Hence an error.
5)
main() { extern out; printf("%d", out); } int out=100;
Answer:
100
Explanation:
This is the correct way of writing the previous program.